Asked by god'scare victor

a body moving with an inertia velocity of 30m/s accelerate uniformly at a rate of 10m/s until it attends a velocity of 50m/s.what is the distance covered during this period?
Answered by Steve
it takes (50-30)/10 = 2 seconds to reach the final velocity.

s = 30t + 1/2 t^2

Now just plug in t=2.
Answered by Gift
Give them answer
Answered by Samuel
How pls solve
Answered by Hosea
No
Answered by Firdausi
A body moving with an intertia velocity of 30/s accelerate uniformly at a rete of 10m/s until it attend a velocity of 50m/s . What is the distance covered during the period?
Answered by Adio
Very good
Answered by Chiamaka
A body moving with anlnitial velocity of 30ms-1 accelerates uniformly at a rate of 10ms-1 until it atlains a velocity of 50m-1. What is the distance covered during this period ?V2= U2+2as makes the subject
Answered by Chiamaka
What is heat period
Answered by Anonymous
It takes 50-30รท10=2seconds to reach final velocity

s=ut+1/2at^2
Then u will input the values
s=30t+1/2t^2
Input 2 for t and solve
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