Question

a body moving with an inertia velocity of 30m/s accelerate uniformly at a rate of 10m/s until it attends a velocity of 50m/s.what is the distance covered during this period?
it takes (50-30)/10 = 2 seconds to reach the final velocity.

s = 30t + 1/2 t^2

Now just plug in t=2.
Give them answer
How pls solve
No
A body moving with an intertia velocity of 30/s accelerate uniformly at a rete of 10m/s until it attend a velocity of 50m/s . What is the distance covered during the period?
Very good
A body moving with anlnitial velocity of 30ms-1 accelerates uniformly at a rate of 10ms-1 until it atlains a velocity of 50m-1. What is the distance covered during this period ?V2= U2+2as makes the subject
What is heat period
It takes 50-30÷10=2seconds to reach final velocity

s=ut+1/2at^2
Then u will input the values
s=30t+1/2t^2
Input 2 for t and solve

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