Asked by Israel

Find the sum of the first eight terms of a linear sequence whose first term is 6 and whose last term is 46

Answers

Answered by Steve
Sn = n/2 (A1+An)
= 8/2 (6+46)
Answered by Sofia
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Answered by Sofia
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Answered by ebiere
Good
Answered by SKEIVS
IS IT 208
Answered by Authority
S/n =n/2[A+D]
A=6
D=46
8/2 [6+46]
4[52]
208
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