Question
what is the smallest time in which a 9.00kW motor can lift a 3500 kg elevator to a height of 9.50m? use 10m/s^2 as g.
Answers
Steve
1W = 1J/s = 1N-m/s
so,
3500 kg * 9.8N/kg * 9.50m /(9000N-m/s) = 36.2 s
so,
3500 kg * 9.8N/kg * 9.50m /(9000N-m/s) = 36.2 s
TurtleBoi
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