Asked by kayla
the population of a southern city follows the exponential law. If the population doubled in size over an 18 month period and the current population in 10000, what will be the population 2 years from now?
the equation for the exponential equation is: A=ao e ^ -kt
ao is the original amount
a is what the population will be
t is the amount of time
k is the rate of growth
the equation for the exponential equation is: A=ao e ^ -kt
ao is the original amount
a is what the population will be
t is the amount of time
k is the rate of growth
Answers
Answered by
Reiny
I don't see why the exponent is negative since this an exponentional growth, the negative usually indicates decay.
Anyway...
I would use A = a (e^kt), where t is months
using << the population doubled in size over an 18 month period >>
2 = 1(e^18k)
ln 2 = 18k
k = ln 2/18
so A = 1000 (e^(24*ln2/18))
= 1000(2.51984)
= 2520
another way would be to use
A = 1000(2)t/k and put in t=24
A = 1000(2^1.3333333)
= 2520
Anyway...
I would use A = a (e^kt), where t is months
using << the population doubled in size over an 18 month period >>
2 = 1(e^18k)
ln 2 = 18k
k = ln 2/18
so A = 1000 (e^(24*ln2/18))
= 1000(2.51984)
= 2520
another way would be to use
A = 1000(2)t/k and put in t=24
A = 1000(2^1.3333333)
= 2520
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