Asked by Alexis

I cannot figure this out for the life of me. Maybe I am overthinking it.

Money is transferred into an account at the rate of R(t)=5000t(e^-0.6t)

If the account pays 2% interest compounded continuously, how much will accumulate in the account over a 9-year period?

Answers

Answered by Steve
Money at 2% grows like e^0.02t

The amount deposited at time t gets to grow for (9-t) years. Seems to me like the account balance after 9 years is thus

∫[0,9] R(t) * e^(.02(9-t)) dt
Answered by Steve
I may have misspoken. Take a look here for a discussion of the topic.

faculty.atu.edu/mfinan/2243/business65.pdf
Answered by Steve
actually, it appears I was right after all...
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