you are solving,
6750(1.05)^t = 8000
1.05^t = 1.185185..
take log of both sides, and use log rules
t = log 1.185185.../log 1.05 = 3.482239
so that is 3 years and .482239 years
multiply the decimal part by 12 to get
3 years, 5.7868.. months
so 3 years, 5 months and .7868 months
multiply the decimal by 30
= 3 years, 5 months, and appr 24 days
which is not the answer.
What does S.I. stand for ?
if it continuous at 5%, then
6750 e^.05t = 8000
take ln of both sides
.05t = ln 1.185185..
t = 3.39798.. which is even less of a time than above.
ahhh, does S.I. mean simple interest???
let's see
6750 + 6750(.05)t = 8000
337.5t = 1250
t = 3.7037 years
= 3 years, .7037(12)months
= 3 years, 8.4444months
= 3 years, 8 months + .444.. months
= 3 years, 8 months, and 13.3333 days
= 3 years, 8 months and 13 1/3 days
Who still uses simple interest for times greater than 1 year ??
in how many years will rs. 6750 amount to rs. 8000 at 5 percent S.I. ? the answer is 3 years 8 months 13 and half days but i don't know the process please give answer.
6 answers
Thanks reiny too much
Tomorrow is.my exam
S.I =A-P
=8000-6750
=1250
S.I=PTR/100
T=SI *100/P*R
= 125000/6750*5
= 3.7037
3years .....
=8000-6750
=1250
S.I=PTR/100
T=SI *100/P*R
= 125000/6750*5
= 3.7037
3years .....
This is a very helpful answer for mine
Please solve