Ask a New Question

Asked by james

For all x in the interval [-11,13] the function f is defined by x^3(x+3)^4

On which two intervals is the function increasing?

Find the region in which the function is positive
16 years ago

Answers

Answered by drwls
Evaluate the derivative of f. The function is increasing where the derivative >0. It increases for x between -11 and -3 and between 0 and +13

The points where f(x) = 0 are x=0 and x=-3. At x>0, it is positive.
16 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions

What interval would you use on a line graph that's range is +13~+42? csc^2 x = 5 over the interval 0 <= x < 2pi 1. 26.57 degs 2. 153.43 degs I think the solutio... f(x) = cos(x) on the interval [−2π, 2π] (a) Find the x-intercepts of the graph of y = f(x).... If X and Y are in the interval (0,pie/2) and sin x =3/2 and cosy =12/13 evaluate each of the followi... 1. Over which interval is the velocity greatest? FILL IN THE BLANK ____ 2. Over which interval(s... In the interval 0 'less than or equal to' x 'less than or equal to' pi find the values that s... using the interval [0,2pi] and f(x) = sinx + cosx, obtain c £ (0,2pi) that satisfies the conclusion... Where on the interval [0,pi/4] is the function f(x)=(7x+3)/(cos(4x)) continuous? Using interval not... On which interval is log(5 – x) negative? What is 9-|x+4|<5 in interval and set notation?
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use