Question

9.0/1 points | Previous Answers SSTCalc6 2.3.046.My Notes
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Let
f(x) =

4x2 if x > 2
4x + 3 if x ≤ 2.


Show that f is continuous from the left at
x = 2,
but not from the right.

lim f(x) =
n→2−



f(2) =


lim f(x) =
n→2+


Answers

4x+3 = 11 at x=2
4x^2 = 16 at x=2

Since f(x) = 4x+3 for x <= 2, lim(x->2-) f(x) = 11 = f(2)

But lim(x->2+) = 16 ≠ 11

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