Asked by neha reddy
Give possible values for length and breadth of the rectangle whose area is -x square+7x+30
Answers
Answered by
Reiny
I read that as
area = -x^2 + 7x + 30
this has to be positive, so
-x^2 + 7x + 30 > 0
x^2 - 7x - 30 < 0
(x - 10)(x+3) < 0
so you know that -3 < x < 10
that is, x must be between -3 and 10
Possible values :
let x = 1, then area = -1 + 7 + 30 = 36
the rectangle is 1 by 36/1 or 1 by 36
let x = 2, then area = -4 + 14 + 30 = 40
the rectangle is 2 by 40/2 or 2 by 20
etc, there will be an infinite number of cases
area = -x^2 + 7x + 30
this has to be positive, so
-x^2 + 7x + 30 > 0
x^2 - 7x - 30 < 0
(x - 10)(x+3) < 0
so you know that -3 < x < 10
that is, x must be between -3 and 10
Possible values :
let x = 1, then area = -1 + 7 + 30 = 36
the rectangle is 1 by 36/1 or 1 by 36
let x = 2, then area = -4 + 14 + 30 = 40
the rectangle is 2 by 40/2 or 2 by 20
etc, there will be an infinite number of cases
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