Asked by eduardo
You decide to repeat Archimedes experiment and determine the density of a candle holder. you suspend it from a spring scale and scale reads 8.0N. You then lower the holder into a tub of water until completely submerged and it reads 5.0N. what is the volume and density of the candle holder? What does the scale read when the holder is 75% submerged in water.
8.0N-5.0N=3.0N
I know buoyant force=density*volume*gravity for fluid
8.0N-5.0N=3.0N
I know buoyant force=density*volume*gravity for fluid
Answers
Answered by
Henry
8 - 5 = 3 N. M*g = 3, M = 3/9.8 = 0.306 kg = Mass of water displaced.
V*D = 306 grams.
V*1 = 306, V = 306 cm^3. volume of water displaced = volume of candle holder.
M*g = 8 N. M = 8/g = 8/9.8 = 0.816 kg = Mass of candle holder.
D = 816g/306cm^3 = 2.67 g/cm^3.
V*D = 306 grams.
V*1 = 306, V = 306 cm^3. volume of water displaced = volume of candle holder.
M*g = 8 N. M = 8/g = 8/9.8 = 0.816 kg = Mass of candle holder.
D = 816g/306cm^3 = 2.67 g/cm^3.
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