Asked by Tyler
Accomplished silver workers in India can pound silver into incredibly thin sheets, as thin as 3.00 x 10-7 m (about one hundredth of the thickness of a sheet of paper). Find the area of such a sheet that can be formed from 3.70 kg of silver.
Answers
Answered by
ay lmao
1.) Look up the density of Silver which is: 10.5 * 10^3 kg/m^3
2.) Now find Volume using the formula Density = Mass/Volume. You should get 3.52 * 10^-4 m^3
3.) The Volume of such a sheet is simply (thickness * area). V=l*A
4.) We already know Volume (3.52*10^-4 m^3) and thickness (3*10^-7m).
5.) So the area of this sheet should be: A=V/l = 1,174.6 m^2
2.) Now find Volume using the formula Density = Mass/Volume. You should get 3.52 * 10^-4 m^3
3.) The Volume of such a sheet is simply (thickness * area). V=l*A
4.) We already know Volume (3.52*10^-4 m^3) and thickness (3*10^-7m).
5.) So the area of this sheet should be: A=V/l = 1,174.6 m^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.