Accomplished silver workers in India can pound silver into incredibly thin sheets, as thin as 3.00 x 10-7 m (about one hundredth of the thickness of a sheet of paper). Find the area of such a sheet that can be formed from 3.70 kg of silver.

Answer 1

1.) Look up the density of Silver which is: 10.5 * 10^3 kg/m^3
2.) Now find Volume using the formula Density = Mass/Volume. You should get 3.52 * 10^-4 m^3
3.) The Volume of such a sheet is simply (thickness * area). V=l*A
4.) We already know Volume (3.52*10^-4 m^3) and thickness (3*10^-7m).
5.) So the area of this sheet should be: A=V/l = 1,174.6 m^2