Asked by Sadie
For the reaction CS2+3Cl2=CCl4+S2Cl2, calculate the percent yield if 719 g of CCl4 are produced when 410 g of CS2 react w/ an excess of chlorine.
I have absolutely no clue on how to do this!! If I could get some help that would be great!!
I have absolutely no clue on how to do this!! If I could get some help that would be great!!
Answers
Answered by
bobpursley
the balanced equation indicates it takes 1 mole of CS2 to produce each mole of CCl4.
Moles CS2 should equal moles of CCl4
you have moles of CS2:
410grams/molemass=5.39 moles (check that).
so you should get mass of CCl4:
5.39(molmeassCCl4)=5.39*154=830g check that.
so your precent yield= what you got/what should have been
Moles CS2 should equal moles of CCl4
you have moles of CS2:
410grams/molemass=5.39 moles (check that).
so you should get mass of CCl4:
5.39(molmeassCCl4)=5.39*154=830g check that.
so your precent yield= what you got/what should have been
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