Asked by Anonymous
Find the sum of 35 terms of an arithmetic series of which the first term is "a" and the fifteenth term is "9a."
Answers
Answered by
Reiny
1st term --- a
15th term = a + 14d = 9a
14d = 8a
d = 4a/7
sum(35) = (35/2)(2a + 34d)
= (35/2)(2a + 34(4a/7)
= (35/2)(150a/7)
= 375a
15th term = a + 14d = 9a
14d = 8a
d = 4a/7
sum(35) = (35/2)(2a + 34d)
= (35/2)(2a + 34(4a/7)
= (35/2)(150a/7)
= 375a
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