Asked by James
Explain in detail how you would find the density of an unknown high-density object if you had only the objects listed below.If you show calculations, make sure you define your variables.Assume all containers are large enough to hold the object....
You have:
1. - A spring scale (the hanging kind, not a bathroom scale)
- an unmarked bucket containing a liquid of known density (not water)
You have:
1. - A spring scale (the hanging kind, not a bathroom scale)
- an unmarked bucket containing a liquid of known density (not water)
Answers
Answered by
bobpursley
weigh the object
weight the object while it is submerged.
From those two things, you can determine the mass, and the volume.
weight the object while it is submerged.
From those two things, you can determine the mass, and the volume.
Answered by
Damon
weight in water = WW Newtons
weight in air = WA Newtons
mass = WA/9.81 kilograms
(if your scale reads in kilograms, multiply by 9.81 m/s^2 on earth to get Newtons)
difference = WA-WW = buoyant force = volume*density of water * 9.81
density of water = 1,000 kg/m^3
so
difference = 1000*V * 9.81
=9810 V Newtons
so
9810 V = WA-WW
V = (WA-WW)/9810
Mass of object/Volume of object
= density
= [WA/9.81] /[(WA-WW)/9810] kg/m^3
= [WA/(WA-WW) ]1000 kg/m^3
weight in air = WA Newtons
mass = WA/9.81 kilograms
(if your scale reads in kilograms, multiply by 9.81 m/s^2 on earth to get Newtons)
difference = WA-WW = buoyant force = volume*density of water * 9.81
density of water = 1,000 kg/m^3
so
difference = 1000*V * 9.81
=9810 V Newtons
so
9810 V = WA-WW
V = (WA-WW)/9810
Mass of object/Volume of object
= density
= [WA/9.81] /[(WA-WW)/9810] kg/m^3
= [WA/(WA-WW) ]1000 kg/m^3
Answered by
Damon
By the way, GOOGLE Archimedes
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