Asked by James
You want to carry an 800kg object into the air using a helium balloon. What size of a helium balloon (I'm looking for volume) would be required to accomplish such a task? Assume the density of air is 1.25 kg/m3 and the density of helium is 0.18 kg/m3.
Answers
Answered by
bobpursley
the mass of air displaced-mass of helium= 800kg
mass of air displaced=Vol*1.25kg/m^2
mass of helium =Vol*.18kg/m^3
solve for volume.
mass of air displaced=Vol*1.25kg/m^2
mass of helium =Vol*.18kg/m^3
solve for volume.
Answered by
James
V=m/d
I understand how to solve for volume but there doesn't seem to be a definitive mass for air and helium in this answer, can I get some more help please? Or should I just do two equations (1.25=800/v and .18=800/v) but then what do I do? Im a little confused
I understand how to solve for volume but there doesn't seem to be a definitive mass for air and helium in this answer, can I get some more help please? Or should I just do two equations (1.25=800/v and .18=800/v) but then what do I do? Im a little confused
Answered by
Scott
the difference in densities gives you the "lift mass" per m^3
v = 800 kg /
(1.25 kg/m^3 - 0.18 kg/m^3)
v = 800 kg /
(1.25 kg/m^3 - 0.18 kg/m^3)
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