An airplane is flying with a velocity of 240 m/s at an angle of 30.0o with the horizontal,

Question

as the drawing shows. When the altitude of the plane is 2.4 km, a flare is released
from the plane. The flare hits the target on the ground. What is the angle θ?

Answer 1

The vertical and horizontal distance components of the flare are

y = 2400 + 120t - 4.9t^2
x = 207.84t

The flare hits the ground when t=37.54

The tangent of the angle of direction at time t=37.54 is

dy/dx = (120-9.8*37.54)/207.84 = -1.193
So, θ = -50°

I am assuming that the angle in question is the angle at which the flare strikes the ground...