Iw^2=KE
w=677*2PI/60 rad/sec\
solve for I.
rotational inertia then= I w
Calculate the rotational inertia of a wheel that has a kinetic energy of 24,400 J when rotating at 677 rev/min.
I know that I = mr^2 and that
T = Ia; also I calculated 677rpm to be 70.9 radians/sec. But I don't understand how to integrate KE into this.
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