Asked by Robert
Assume you have a canon aimed straight up. The cannonball is shot at a velocity
of v_0=69 m/s.
How high does the cannonball go?
How much time does it take the cannonball to reach that height?
of v_0=69 m/s.
How high does the cannonball go?
How much time does it take the cannonball to reach that height?
Answers
Answered by
Henry
V^2 = Vo^2 + 2g*h.
0 = 69^2 - 19.6h, h = ?.
V = Vo + g*t.
0 = 69 - 9.8t, t = ?.
0 = 69^2 - 19.6h, h = ?.
V = Vo + g*t.
0 = 69 - 9.8t, t = ?.
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