Asked by haya
A ball is thrown horizontally from a window 27 m above the ground. The ball strikes the ground at a point 80 m from the base of the building. The acceleration due to gravity is 9.8 m/s2. What is the resultant velocity of the ball just before it strikes the ground?
37.76 m/s
25.72 m/s
41.12 m/s
53.41 m/s
52.24 m/s
37.76 m/s
25.72 m/s
41.12 m/s
53.41 m/s
52.24 m/s
Answers
Answered by
Henry
V^2 = vo^2 + 2g*h.
V^2 = 0 + 19.6*27, V = 23 m/s.
V^2 = 0 + 19.6*27, V = 23 m/s.
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