Asked by Anonymous
find the smallest number which is greater than 111,111,000 and divisible by 8 and 9
Answers
Answered by
bobpursley
add 8, add 3
Answered by
Reiny
To be divisible by 8, the last 2 digits must be divisible by 8,
to be divisible by 9, the sum of the digits must be divisible by 9
so far they add up to 6, so let's add:
3 ---> no good for the 8 part
12 ---> no good for the 8 part
21 ---> no good for the 8 part
30 ---> no good for the 8 part
39 ---> no good for the 8 part
48 ----- YEAHHH
111,111,048
OR
The LCM of 8 and 9 is 72
so any multiple of 72 is good
111,111,000 รท 72 = 1543208 24/72
So if we multiply 72 by the next integer we should have it.
1543209 * 72 = 111,111,048
to be divisible by 9, the sum of the digits must be divisible by 9
so far they add up to 6, so let's add:
3 ---> no good for the 8 part
12 ---> no good for the 8 part
21 ---> no good for the 8 part
30 ---> no good for the 8 part
39 ---> no good for the 8 part
48 ----- YEAHHH
111,111,048
OR
The LCM of 8 and 9 is 72
so any multiple of 72 is good
111,111,000 รท 72 = 1543208 24/72
So if we multiply 72 by the next integer we should have it.
1543209 * 72 = 111,111,048
Answered by
bobpursley
Reiny is correct, I did not read the problem as divisible by 8 and 9 both, but sequentially, as in two numbers.
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