fnear+ffar=3350+811 N
now sum moments around any point, lets do it from the near end.
811*1/6-ffar*1=0
solve for ffar, then use the first equation for fnear
A hiker, who weighs 811 N, is strolling through the woods and crosses a small horizontal bridge. The bridge is uniform, weighs 3350 N, and rests on two concrete supports, one on each end. He stops 1/6 of the way along the bridge. What is the magnitude of the force that a concrete support exerts on the bridge (a) at the near end and (b) at the far end?
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