Question
a force F applied to an object of mass m1 produces an acceleration of 3.30m/s^2. the same force applied to a second object of mass m2 produces an acceleration of 1.5m/s^2
if m1 and m2 are combined, find their acceleration under the action of the force F.
if m1 and m2 are combined, find their acceleration under the action of the force F.
Answers
Damon
m1 = F/3.3
m2 = F/1.5
so
(m1+m2) = F(1/3.3 + 1/1.5) = .970 F
a = F/(.970 F) = 1.03 m/s^2
m2 = F/1.5
so
(m1+m2) = F(1/3.3 + 1/1.5) = .970 F
a = F/(.970 F) = 1.03 m/s^2
drwls
The mass m2 is larger than m1 by a factor
3.30/1.50 = 2.2
The combined mass m1 + m2 is therefore
m1 + 2.2m1 = 3.2 m1
When the same force F acts, acceleration will be ne 3.2 tikmes less than when it acted on m1, or
a = 3.30 m/s^2/3.2 = 1.03 m/s^2
3.30/1.50 = 2.2
The combined mass m1 + m2 is therefore
m1 + 2.2m1 = 3.2 m1
When the same force F acts, acceleration will be ne 3.2 tikmes less than when it acted on m1, or
a = 3.30 m/s^2/3.2 = 1.03 m/s^2