Asked by luc
so, (3.75)(4) + (.5)(3.75)(49) or 106.875 radians
that's not the correct answer, so is it just the second part to find the additional angle?
(.5)(3.75)(49) = 91.875 but it too is incorrect, what am I missing?
that's not the correct answer, so is it just the second part to find the additional angle?
(.5)(3.75)(49) = 91.875 but it too is incorrect, what am I missing?
Answers
Answered by
bobpursley
yes that is wrong.
for displacment, the additional displacement,
d=wi*7+1/2 alpha t^2
where wi is the angular rotation at the end of the first four seconds. I can't find the post which I need to put a number on it, but as I recall, you had an angular acceleration for a time period to get that wf, now a wi.
for displacment, the additional displacement,
d=wi*7+1/2 alpha t^2
where wi is the angular rotation at the end of the first four seconds. I can't find the post which I need to put a number on it, but as I recall, you had an angular acceleration for a time period to get that wf, now a wi.
Answered by
luc
The angular velocity after 4s is 15r/s
so would it be
15(7) + .5(3.75)(49) = 196.875?
so would it be
15(7) + .5(3.75)(49) = 196.875?
Answered by
luc
It is! Thanks for your help
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