Asked by Diane
                Gent dose at 10:26am over 30 minutes and levels were reported as 3.6 at 13:07 and 1.2 at 16:59. Calculate k. 
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                    Answered by
            bobpursley
            
    K=ln(3.6/1.2)/timeelapsed
k=ln(3)/(1307-1056)=ln(3)/2:11
k= ln(3)/(131min) or ln3/2.18 hr
    
k=ln(3)/(1307-1056)=ln(3)/2:11
k= ln(3)/(131min) or ln3/2.18 hr
                    Answered by
            Diane
            
    K=0.50 is this correct? 
    
                    Answered by
            bobpursley
            
    yes, but you need to include units:
.50/hr
    
.50/hr
                    Answered by
            Diane
            
    Thank you! 
    
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