Asked by Lucille
I am reposting my question. Thank you Bob for explaining how to write it..
In ASCII format:
(8x^2y^0z^6)2^ + 3x^2z^12 + 5y^0z^12
64x4^y2^z8^ + 3x2^ + z12^ + 5y0^z12^
64x6^ + 5y2^ + z32^
Please let me know if these makes sense now. Thank you
In ASCII format:
(8x^2y^0z^6)2^ + 3x^2z^12 + 5y^0z^12
64x4^y2^z8^ + 3x2^ + z12^ + 5y0^z12^
64x6^ + 5y2^ + z32^
Please let me know if these makes sense now. Thank you
Answers
Answered by
bobpursley
8x^2y^0z^6)2^ + 3x^2z^12 + 5y^0z^12
64x4^y2^z8^ + 3x2^ + z12^ + 5y0^z12^ No. the first term y will be at the zero power (O x 2=0) Z will be to the 12th power (6x2=12)
do that, then gather terms.
64x4^y2^z8^ + 3x2^ + z12^ + 5y0^z12^ No. the first term y will be at the zero power (O x 2=0) Z will be to the 12th power (6x2=12)
do that, then gather terms.
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