Asked by gugtrt

My pizzeria offers

pizzas in 3 sizes (S/M/L)
7 different meat toppings
5 different vegetable toppings
4 different kinds of cheese.
How many different pizza orders are possible if we must pick a size, 1 meat, 2 different vegetables, and 1 kind of cheese?
Answered by gugtrt
300
Answered by Reiny
The order of these items does not matter so I will use combinations
Size -- C(3,1) = 3
meats --C(7,1) = 7
veggies --C(5,2) = 10
cheese -- C(4,1) = 4

number of pizzas = 3x7x10x4 = 840
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