Asked by Saad
A 5.0 uF capacitor is charged to a p.d of 10v. It is then removed from the supply and connected in parallel with an uncharged 20 uF capacitor. Calculate the charge on each capacitor after connection
(My working so far,
5×10^-6×10=5×10^-5C )I am stumped on what to do any further
(My working so far,
5×10^-6×10=5×10^-5C )I am stumped on what to do any further
Answers
Answered by
bobpursley
charge stored: 5E-5 (CV)
now, when connected, the two capacitors have equal voltages..
V=Q1/C1 =Q2/C2
but Q1+Q2= original charge , or
Q1+Q2=(5E-6 *10)
q2=5E-5-Q1
V=Q1/C1 =Q2/C2
Q1=C1/C2 * (5E-5-Q1) and C1/C2=1/4
which leads to
5/4 Q1=1/4*(5E-5)
Q1=.... then solve for Q2
now, when connected, the two capacitors have equal voltages..
V=Q1/C1 =Q2/C2
but Q1+Q2= original charge , or
Q1+Q2=(5E-6 *10)
q2=5E-5-Q1
V=Q1/C1 =Q2/C2
Q1=C1/C2 * (5E-5-Q1) and C1/C2=1/4
which leads to
5/4 Q1=1/4*(5E-5)
Q1=.... then solve for Q2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.