Asked by Vivek
A rectangular Park of length 80m and width 65m has two paths of uniform width 2.5m crossing each other. Find the area of remaining portion.
Answers
Answered by
John1
The area is 80 x 65 = 5200
Path 1 is 2.5 times 80
Path 2 is 2.5 times 65
find these two areas and subtract from the 5200
Path 1 is 2.5 times 80
Path 2 is 2.5 times 65
find these two areas and subtract from the 5200
Answered by
Himanshi Gajbhiye
Sir , mam this answer are correct But , you have use short method (kuch samjhe nahi aa Raha ha) ############# regard
Answered by
Heer
Length of rectangular park = 80 m
Breadth of rectangular park = 65 m
Uniform width of path = 2.5 m
Area of rectangular park = l x b = 80m x 65 m = 5200 sq.m.
Path 1 ( ABCD ) = 80 m
Path 2 ( EFGH ) = 65 m
AB = 2.5 m and AD = 80 m
EH = 2.5 m and EF = 65 m
KLMN which is the square between two cross-roads
KL = 2.5 m and KN = 2.5 m
Area of the path = Area of rectangle ABCD + Area of the rectangle EFGH - Area of the square KLMN
= AD x AB + EF x EH - KL x KN
= (80 x 2.5 + 65 x 2.5 - 2.5 x 2.5) sq.m.
= (200 + 162.5 - 6.25) sq.m.
= 356.25 sq.m.
Area of rectangular park - Area of roads = Area of the remaining portion of park
= 5200 sq.m. - 356.25 sq.m.
= 4,843.75 sq.m. is the area of remaining portion of the park.
Breadth of rectangular park = 65 m
Uniform width of path = 2.5 m
Area of rectangular park = l x b = 80m x 65 m = 5200 sq.m.
Path 1 ( ABCD ) = 80 m
Path 2 ( EFGH ) = 65 m
AB = 2.5 m and AD = 80 m
EH = 2.5 m and EF = 65 m
KLMN which is the square between two cross-roads
KL = 2.5 m and KN = 2.5 m
Area of the path = Area of rectangle ABCD + Area of the rectangle EFGH - Area of the square KLMN
= AD x AB + EF x EH - KL x KN
= (80 x 2.5 + 65 x 2.5 - 2.5 x 2.5) sq.m.
= (200 + 162.5 - 6.25) sq.m.
= 356.25 sq.m.
Area of rectangular park - Area of roads = Area of the remaining portion of park
= 5200 sq.m. - 356.25 sq.m.
= 4,843.75 sq.m. is the area of remaining portion of the park.