Asked by Mike Smith

write an equation of the line passing through the point (8,7) that is perpendicular to the line y+7=-7/17(x+8)
Answered by Damon
y = -(7/17)x + some old constant
slope m = -7/17
slope of perpendicular = -1/m = 17/7

y = 17 x/7 + b

7 = 17*8/7 + b
49 = 136 + 7 b
7b = -87
b = -87/7

7 y = 17 x - 87
Answered by nina
y=7/17x+7
Answered by nina
y=17/7x-87/7
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