Asked by Anonymous
A baseball hit just above the ground leaves the bat at 27 m/s at 45∘ above the horizontal.
How far away does the ball strike the ground?
How much time is the ball in the air?
How far away does the ball strike the ground?
How much time is the ball in the air?
Answers
Answered by
Damon
Vi = 27 sin 45
u = 27 cos 45
h = Vi t - 4.9 t^2
at ground h = 0
0 = Vi t -4.9 t^2 = t (Vi-4.9t)
t = Vi/4.9
then
range = u t
u = 27 cos 45
h = Vi t - 4.9 t^2
at ground h = 0
0 = Vi t -4.9 t^2 = t (Vi-4.9t)
t = Vi/4.9
then
range = u t
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