Asked by Lina
Now sure how to do this!
1. DESCRIBE & CALCULATE how to make 750. mL of a 1.25 M sucrose solution
2. Concentrated HCl has a molarity of 12 M. DESCRIBE & CALCULATE how to make 1.50 L of a 3.00 M HCl.
1. DESCRIBE & CALCULATE how to make 750. mL of a 1.25 M sucrose solution
2. Concentrated HCl has a molarity of 12 M. DESCRIBE & CALCULATE how to make 1.50 L of a 3.00 M HCl.
Answers
Answered by
bobpursley
a. 1.25M=molesSucrose/.75
moles Sucrose=1.25*.75
grams sucrose= molesSucrose*342.3
put sucrose in a beaker, add water to 750ml mark, stir, and label.
2. You want 1.50L, so in that you have 1.50*3 moles HCL, or 4.5moles
determine the volume of 12 molar in which you get 4.5moles
4.5/volume=12
volume=4.5/12 liters=375ml
so, always adding acid to water, put about 900mlof water in a beaker, add 375ml 12 molar acid slowly, stiring. When mixed, add water up to the 1.5Liter mark. label, and safely store.
moles Sucrose=1.25*.75
grams sucrose= molesSucrose*342.3
put sucrose in a beaker, add water to 750ml mark, stir, and label.
2. You want 1.50L, so in that you have 1.50*3 moles HCL, or 4.5moles
determine the volume of 12 molar in which you get 4.5moles
4.5/volume=12
volume=4.5/12 liters=375ml
so, always adding acid to water, put about 900mlof water in a beaker, add 375ml 12 molar acid slowly, stiring. When mixed, add water up to the 1.5Liter mark. label, and safely store.
Answered by
Lina
Is 1 or part A's answer then 321
and question 2's answer is 375...??
and question 2's answer is 375...??
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.