Asked by Zoi

27. Part A. Make a punnett square (as best as you can in this online format) and cross parents both with the thumb genes Aa (A=normal thumb, a=hitchhikers thumb) and show the results. (1 pt)
A a
A AA Aa
a Aa aa

27 Part B. (1 pt) Approximately what percentage of their children would have a hitchhikers thumb?
Approximately 25% percent of their children would have a hitchhikers thumb.


27 Part C. (1 pt) What percentage of their offspring shown in your punnett square COULD have a child with a hitchhikers thumb assuming they reproduced with someone carrying the "a" allele? Note: EC may be awarded for well detailed answers!

Answers

Answered by Zoi
Please check my punnet square


A a

A AA Aa

a Aa aa


and if the percentage I cam up with is correct for part b. I really don't understand part c so please explain that to me!!! Thank you!
Answered by bobpursley
a, and b parts are ok
part c

aa x Aa
offspring then aA,aa, aA, aa or half will have aa
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