The reaction is...
2MnO4−+5H2C2O4+6H+>>2Mn2++10CO2
+8H2O.
Normally, a drop or two of sulfuric acid is added to provide the H+ ion, however, if you have excess oxalic acid, it should provide enough.
So you had 4 drops , diluted with 10 drops, to a new volume of 14 drops. So Molarity before the reaction will be .25*(4/14). Now as the reaction goes to completion, no permanganate ion remains.
yes, the 2 drops of oxalic acid, and 8 drops of water are mostly diluting water.
Calculate the MnO4- concentration of the diluted sample when the sample is prepared in the following manner: Add 2 drops oxalic acid, 4 drops permanganate and 8 drops water. The original permanganate is 0.25M.
I don't understand how to do this, any help would be appreciated.
1 answer
1 answer