Asked by jaime
find the limit without using L'Hopital's Rule
Lim(X->-4) (16-x^2 / x+4)
Lim(X->-4) (16-x^2 / x+4)
Answers
Answered by
Damon
No need for L'Hopital
16-x^2 = (4-x)(4+x)
so you really have:
(4-x) at x = -4
4-(-4) = 8
16-x^2 = (4-x)(4+x)
so you really have:
(4-x) at x = -4
4-(-4) = 8
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