Question

An airplane traveling horizontally at 367 km/hr at a height of 1 km releases a bomb. How far ahead (to the nearest meter) from the release point does the bomb strike the ground?

bobpursley
time to fall 1000 m: d=1/2 g t^2
t=2d/g=2000/9.8 seconds

367km/hr=367/3.6 m/s

d=v*t=367/3.6 * 2000/9.8 meters

Related Questions

A bomber is flying horizontally over level terrain at a speed of 250 m/s relative to the ground and... an airplane is traveling horizontally 500 m/s at an altitude of 3000 meters. what's the distance the... A bomber in level flight, flying at 92m/s, releases a bomb at a height of 1950m. (a) How long is...