Asked by krish ferrer
A pedestrian is an between two tall building, from a point 10 meter high on the first building, the angle of depression of the pedestrian is 20°,10' from the same point, the angle of elevation of the top of the second building is 15°,20'. If the two building are 40 meter apart. How far is the pedestrian from second building?
Answers
Answered by
Steve
If the pedestrian is x meters from the short building,
10/x = tan20°10'
the distance to the tall building is 40-x
You don't seem to care how tall the other building is, but if the tall building has height h, then
(h-10)/40 = tan15°20'
10/x = tan20°10'
the distance to the tall building is 40-x
You don't seem to care how tall the other building is, but if the tall building has height h, then
(h-10)/40 = tan15°20'
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