Question

A family left their house in two cars at the same time. One car traveled at an average of 7 miles per hour faster than the other. When the first car arrived at the destination after 5 & 1/2 hours of driving, both cars had driven 599.5 miles. If the second car continues at the same average speed, how much time to the nearest minute before the second car arrives?
How need to find a TIME?

Answer 1

You are given the time it took for the first car to go 599.5 miles in 5.5 hours.
Using rate = distance/time
the rate of the first car is 599.5/5.5 = 109 mph
So the slower car went at 102 mph

And the slower car would take 599.5/102 hrs
or 5.87745 hrs or 5 hrs and 53 minutes

5:53 - 5.30 = 0:23

Answer 2

@Reiny how did you convert 5.87745 into 5 hours and 53 minutes?