Asked by Belle
How many grams of AlCl3 are produced when 53.0 g of Al reacts?
Answers
Answered by
bobpursley
moles of Al=53/27
moles of AlCl3 = same
mass AlCl3=molesAlCl3*molmassAlCl3
moles of AlCl3 = same
mass AlCl3=molesAlCl3*molmassAlCl3
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