Question
How many grams of AlCl3 are produced when 53.0 g of Al reacts?
Answers
bobpursley
moles of Al=53/27
moles of AlCl3 = same
mass AlCl3=molesAlCl3*molmassAlCl3
moles of AlCl3 = same
mass AlCl3=molesAlCl3*molmassAlCl3