Asked by Jay
Sasha is driving straight and notices an antelope in the road a ways off. Determine the stopping distance (from the time she sees the antelope) for her car with an initial speed of 95 km/hr and an acceleration of -4.0 m/s2. Sasha's reaction time to start breaking is 1.0 second.
Answers
Answered by
Steve
recall that the equation for distance is
s = vt + a/2 t^2
95 km/hr = 26.39 m/s
So, it will take 26.39/4 = 6 seconds of braking to stop.
s = 95*7 - 2*6^2 = 593 meters to stop
I guess she had good eyes, seeing an antelope at half a km away! Or, maybe she just hit it, or swerved past at the end...
s = vt + a/2 t^2
95 km/hr = 26.39 m/s
So, it will take 26.39/4 = 6 seconds of braking to stop.
s = 95*7 - 2*6^2 = 593 meters to stop
I guess she had good eyes, seeing an antelope at half a km away! Or, maybe she just hit it, or swerved past at the end...
Answered by
Steve
sorry. 26.39/4 = 6.59
don't know how I got so far off. So, fix t and redo the calculation...
don't know how I got so far off. So, fix t and redo the calculation...
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