Question

A load of 12 kg stretches 15 cm and a load of 30 kg stretches 18 cm. Find the natural (unstretched) length of the spring.
K = (M2-M1)/(d2-d1) = (30-12)/(18-15) = 6 kg/cm .

d = (12kg/6kg) * 1cm = 2 cm.

L + 2 = 15, L = 13 cm.


Related Questions

a load of 8 kg attached to the bottom of a coil spring stretches the spring to a length of 76 cm and... If a load of 1kg stretches a load by 1.2m, what is the force constant of the load? An elastic string stretches to a total length of 30cm under a load of 500N. With an additional load... Stretches that do not involve motion and are held for a brief period of time are called: (1 point)...