Asked by Fred

Electric circuit with three cells each of emf 2v and negligible internal resistances are connected in series with an ammeter two resistors of resistance 2 and 6 and a key.
1. Draw a diagram for the above information
2.calculate the current in the circuit when the key is closed
Answered by Damon
6 volt battery
resistance of 8 ohms

I assume the resistors are also in series

i = 6/8 = 3/4 = 0.75 amps
Answered by Gyamfi
Answers
Answered by Gyamfi
Answer
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