Asked by Andrew
A gas mixture consists of equal masses of methane (molecular weight 16.0) and argon (atomic weight 40.0). If the partial pressure of argon is 200. torr, what is the pressure of methane, in torr?
Answers
Answered by
Damon
P V = n R T
n is number of mols
say we have 1 mol (n=1) of argon, 40 grams
then we have 40 grams of Methane
which is 40/16 or 2.5 mols (n=2.5)
they both have the same V and T
P/n = RT/V = same for each
200/1 = Pmeth/2.5
Pmeth = 2.5*200 = 500 torr
n is number of mols
say we have 1 mol (n=1) of argon, 40 grams
then we have 40 grams of Methane
which is 40/16 or 2.5 mols (n=2.5)
they both have the same V and T
P/n = RT/V = same for each
200/1 = Pmeth/2.5
Pmeth = 2.5*200 = 500 torr
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