Question
if you burned 3.0 g of magnesium and produced 5.0 g of product how much oxygen gas was used ?
Answers
Damon
2Mg + O2 ---> 2 MgO
Mg = 24.3 g/mol
O = 16 g/mol
so
48.6 grams Mg + 32 grams O2 --> 80.6 grams MgO
5/80.6 = .062 mol MgO produced
x/32 = .062
x = 1.985 grams O2
and we needed
y/48.6 = .062
y = 3.00 grams of Mg sure enough
Mg = 24.3 g/mol
O = 16 g/mol
so
48.6 grams Mg + 32 grams O2 --> 80.6 grams MgO
5/80.6 = .062 mol MgO produced
x/32 = .062
x = 1.985 grams O2
and we needed
y/48.6 = .062
y = 3.00 grams of Mg sure enough