Asked by Erin
Iron (III) Oxide reacts with Aluminum to form Aluminum Oxide and Iron. If I have 255 g of Aluminum and unlimited Iron (III) oxide, how many grams of Iron will form?
I am really not sure how to work with this. What does it mean when it says that the iron is unlimited, how would you calculate that in? I am unsure how to convert to moles and calculate grams on this one.
I am really not sure how to work with this. What does it mean when it says that the iron is unlimited, how would you calculate that in? I am unsure how to convert to moles and calculate grams on this one.
Answers
Answered by
Damon
Fe2O3 + Al ---> Al2O3 + Fe
same number of mols of Fe as of Al
Al = 30 g/mol
so 225/30 mols of Al
so 225/30 mols of Fe
so
(225/30) mol mass of Fe
(225/30)56 = 420 grams of iron
same number of mols of Fe as of Al
Al = 30 g/mol
so 225/30 mols of Al
so 225/30 mols of Fe
so
(225/30) mol mass of Fe
(225/30)56 = 420 grams of iron
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.