initial momentum=final momentum
(2080+1240)4660=2080*V+1240*5570
solve for V
A two-stage rocket moves in space at a constant velocity of +4660 m/s. The two stages are then separated by a small explosive charge placed between them. Immediately after the explosion the velocity of the 1240-kg upper stage is +5570 m/s. What is the velocity (magnitude and direction) of the 2080-kg lower stage immediately after the explosion?
1 answer