Asked by Tyler

The hail comes straight down at a mass rate of m/Δt=0.0690 kg/s and an initial velocity of v0= -15.0 m/s. Suppose that the hail described there bounces off the roof of the car with a velocity of +14.0 m/s. Ignoring the weight of the hailstones, calculate the magnitude of the force exerted by the hail on the roof
Answered by Eddie
F=m1v1-m2v2

0.069 times the change in velocity
0.069(29)=2.001. Newtons third law= your answer -2.001
I can't really explain it but that's how you find the answer.
Answered by Anonymous
@eddie yea i tried this and got the right answer but i wish i knew why u do that. does it have anything to do with impulse = change in momentum, or p (momentum) = m*v? idk
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