Question
A cart full of packages weighing 180 pounds is rolling down a ramp 12 feet long at an incline of 25° (the force applied by gravity is equal to the weight of the package). Find the work done by gravity as the cart moves the length of the ramp. Assume that friction isn't a factor.
Answers
the vertical distance moved is
12 sin25° = 5.07 ft
Work = PE lost = 5.07 * 180 ft-lb
12 sin25° = 5.07 ft
Work = PE lost = 5.07 * 180 ft-lb
Thank you. I wasn't sure how to put the information given into equations.
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