Asked by David
28cm3 of a gas weighs 0.4g at STP.Calculate the molecular mass of the gas.
Answers
Answered by
Steve
well, 1 mole fills 22.4L
28cm^3 = 0.028L
So, you have .028/22.4 = 0.00125 moles (1/800 moles)
Thus, if the mol wt is x grams,
x/800 = 0.4
x = 320
28cm^3 = 0.028L
So, you have .028/22.4 = 0.00125 moles (1/800 moles)
Thus, if the mol wt is x grams,
x/800 = 0.4
x = 320
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