Asked by Jazz
The mass of the Earth is 5.98 × 1024 kg. A 6.83 kg bowling ball initially at rest is dropped from a height of 2.12 m. The acceleration of gravity is 9.8 m/s^2. What is the speed of the Earth coming up to meet the ball just before the ball hits the ground?
How do you solve this?
How do you solve this?
Answers
Answered by
Scott
the force of the Earth on the ball is the same as the ball on the Earth
f = m a
use the drop time to find the velocity
v = a t
f = m a
use the drop time to find the velocity
v = a t
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