Asked by Anonymous
if n veries inversely as (y^2-1) and is equal to 24,when y=10. then find the value of n, when y=5
Answers
Answered by
Steve
n = k/(y^2-1)
So, n(y^2-1) = k, a constant.
You want n such that
n(5^2-1) = 24(10^2-1)
24n = 24*99
n = 99
So, n(y^2-1) = k, a constant.
You want n such that
n(5^2-1) = 24(10^2-1)
24n = 24*99
n = 99
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